Question

plzzz ans......Simultaneous equation......Thnk u

Answer 1

32
unit place 2
ten place 3
1/3 of 3 = 1
31 is the desired digit
number + unit digit = 32
31 + 1 = 32

Answer 2

Hi !

Unit digit = x
ten's digit = y =  3x

Let the number be  10y +x

Given , the sum of the number and unit digit = 32

(10y + x ) + x = 32

y = 3x 

10 × 3x + x + x = 32

30x + 2x = 32

32x = 32

x = 1

y = 3x

y = 3

y = 3 , x = 1

the number is :-

10y + x

10×3 + 1 = 30 + 1 = 31

the number is 31