plzzz ans......Simultaneous equation......Thnk u
Attachments:

Answers
Answered by
0
32
unit place 2
ten place 3
1/3 of 3 = 1
31 is the desired digit
number + unit digit = 32
31 + 1 = 32
unit place 2
ten place 3
1/3 of 3 = 1
31 is the desired digit
number + unit digit = 32
31 + 1 = 32
Answered by
1
Hi !
Unit digit = x
ten's digit = y = 3x
Let the number be 10y +x
Given , the sum of the number and unit digit = 32
(10y + x ) + x = 32
y = 3x
10 × 3x + x + x = 32
30x + 2x = 32
32x = 32
x = 1
y = 3x
y = 3
y = 3 , x = 1
the number is :-
10y + x
10×3 + 1 = 30 + 1 = 31
the number is 31
Unit digit = x
ten's digit = y = 3x
Let the number be 10y +x
Given , the sum of the number and unit digit = 32
(10y + x ) + x = 32
y = 3x
10 × 3x + x + x = 32
30x + 2x = 32
32x = 32
x = 1
y = 3x
y = 3
y = 3 , x = 1
the number is :-
10y + x
10×3 + 1 = 30 + 1 = 31
the number is 31
Anonymous:
splendid answer!! keep it up!!
Similar questions