Math, asked by komal555, 8 months ago

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Answered by bavitha333
5

Answer:

 { \sin(30) }^{2}  +  { \cos(30) }^{2}  \\  =  \frac{1}{4}  +  \frac{3}{4}  \\  = 1

 { \sec(45) }^{2}  -  { \tan(45) }^{2} \\  =  { \sqrt{2} }^{2}   -  {1}^{2}  \\  = 1

 { \csc(60) }^{2}  -  { \cot(60) }^{2}  \\  =   { \frac{2}{ \sqrt{3} } }^{2}  -  { \frac{1}{ \sqrt{3} } }^{2}  \\  = 1

 { \sin(45) }^{2}  +  { \cos(45) }^{2}  \\  \frac{1}{2}  +  \frac{1}{2}  \\  = 1

hope \: u \: undrstand \: dear.... \\ please \: mark \: me \: as \: brainliest

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