Question

plzzz ans this numerical from chap first law of motion......plzzz show all steps......Thnk u

Answer 1

Given:

Force=1500 N

Since F= Δp/t

t=2 s

Therefore change in  momentum(Δp)=F*t=1500*2=3000 kg m/s...........(a)

u(initial velocity)=30 m/s

On applying brakes,

v(final velocity)=0(as the body comes to rest) 

Therefore, acceleration=(v-u)/t=(0-30)/2=-30/2=-15 m/s²

Retardation=15 m/s²........................................(b)

∵F=m a

∴m=F/a

> m=1500/15

mass of car=100kg........................................(c)

Hope this helps!