Question

plzzz ans this ques....​

Answer 1

$a = log_{ \sqrt{3} }(8) . log_{4}(81) \\ a = 3 log_{ \sqrt{3} }(2) .8 log_{4}( \sqrt{3} ) \\ a = \frac{24 log_{ \sqrt{3} }(2) }{ log_{ \sqrt{3} }(4) } \\ a = 12 \\ \\ b = log_{ \sqrt{6} }(3) . log_{3}(36) \\ b = 2log_{ \sqrt{6} }( \sqrt{3} ) .4 log_{3}( \sqrt{6} ) \\b = \frac{2}{ log_{ \sqrt{3} }( \sqrt{6} ) } \times \frac{4}{ log_{ \sqrt{6} }(3) } \\ b = \frac{2}{ log_{ \sqrt{3} }( \sqrt{6} ) } \times 2 log_{ \sqrt{3} }( \sqrt{6} ) \\ b = 4\\ a - b = 12 - 4 = 8$