Question

plzzz ans this question...

Answer 1

$\large{\bold{\underline{Hey \: Mate}}}$

E = b - $\frac{x^{2} }{at}$

Where E is the energy = $[ML^{2}T^{-2}]$

x is the distance = [L]

t is the time = [T]

We know that two physical quantity can be added when they have same dimensions.

b has the dimensions of the energy = $[ML^{2}T^{-2}]$

$\frac{x^{2} }{at}$ has the dimensions of energy.

$\frac{x^{2} }{at}$ = $[ML^{2}T^{-2}]$

a = $\frac{[L^{2}]}{[T] \ [ML^{2}T^{-2}]} = [M^{-1}T]$

Dimension of a × b = $[M^{-1}T] \ [ML^{2}T^{-2}] = [L^{2} T^{-1}]$

Answer 2

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