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Ans: Ans: By Pythagoras theorem,
BC^2 = AB^2 + AC^2
BC^2 = 64 + 36
BC = 10 cm
let O be centre .
In triangle AOB
area = 1/2 × 6 × r
= 3r
In triangle AOC
area = 1/2 × 8 × r
= 4r
In triangle AOB
area = 1/2 × 10 × r
= 5r
Area of triangle ABC = 3r + 4r + 5r
1/2 × 6 × 8 = 12r
24 = 12r
r = 2cm
Hope it helps...!!
BC^2 = AB^2 + AC^2
BC^2 = 64 + 36
BC = 10 cm
let O be centre .
In triangle AOB
area = 1/2 × 6 × r
= 3r
In triangle AOC
area = 1/2 × 8 × r
= 4r
In triangle AOB
area = 1/2 × 10 × r
= 5r
Area of triangle ABC = 3r + 4r + 5r
1/2 × 6 × 8 = 12r
24 = 12r
r = 2cm
Hope it helps...!!
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