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a= -25cm/s² = -0.25m/s²
t = 20 s
v = 0m/s
then using the first equation of motion
v= u +at
0 = u + (-0.25)(20)
0=u -5
5m/s = u
now
s = ut +1/2 at²
s = 5×20 + 1/2 (-0.25)(400)
s = 100 + 1/2 (-100)
s = 100 -50 = 50 m
hope this helps
t = 20 s
v = 0m/s
then using the first equation of motion
v= u +at
0 = u + (-0.25)(20)
0=u -5
5m/s = u
now
s = ut +1/2 at²
s = 5×20 + 1/2 (-0.25)(400)
s = 100 + 1/2 (-100)
s = 100 -50 = 50 m
hope this helps
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