Math, asked by Radhika411, 1 year ago

plzzz ans....Thnk u.....PROVE THE FOLLOWING

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Answered by rohitkumargupta
13
HELLO DEAR,

2sec²θ-sec⁴θ-2cosec²θ+cosec⁴θ

=2sec²θ – 2cosec²θ – sec⁴θ + cosec⁴θ

= 2(sec²θ – cosec²θ) – (sec⁴θ –  cosec⁴θ)

= 2(sec²θ – cosec²θ) – (sec²θ – cosec²θ)
(sec²θ + cosec²θ)

= (sec²θ – cosec²θ) [2 – (sec²θ + cosec²θ)]

= (sec²θ – cosec²θ) [2 – (1 + tan²θ + 1 + cot²θ)]

= (1 + tan²θ – 1 – cot²θ) [2 – (2 + tan²θ + cot²θ)]

= (tan²θ – cot²θ) [2 – 2 – tan²θ – cot²θ)]

= (tan²θ – cot²θ) × – [tan²θ + cot²θ)]

= (cot²θ – tan²θ) × [cot²θ + tan²θ)]

= cot⁴θ – tan⁴θ

I HOPE ITS HELP YOU DEAR,
THANKS
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