plzzz ans.......Trignometry......PLZZ ANS ALL PARTS.....thnk u
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mysticd:
5 points too many questions.
plzz tommorow is my exam
i will give u brainlist
:)
plzz ans
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Hi ,
I used x instead of theta.
according to the problem given,
4 sinx = 3 cosx ---( 1 )
sinx / cos x = 3/ 4
tan x = 3/4 --- ( 2 )
we know that
sec² x = 1 + tan² x
= 1 + ( 3/4 )²
= ( 16 + 9 ) / 16
= 25/ 16
sec x = 5/4 ---- ( 3 )
cos x = 4/5 ---( 4 )
since cos x = 1/ sec x
ii ) put ( 4 ) in ( 1 ), we get
4 sin x = 3 × ( 4/5)
sin x = ( 3× 4 ) /( 4 × 5)
sin x = 3/5 --- ( 5 )
iii ) cot² x - cosec² x
= 1 /tan² x - 1 / sin² x
= 1 / ( 3/4)² - 1 / (3/5)²
= ( 16 / 9) - ( 25/ 9)
= (16-25)/9
= -9/9
= -1
iv )4cos² x - 3 sin² x + 2
= 4 × (16/25) - 3 × (9/25) +2
= 64/25 - 27/25 + 2
= ( 64 - 27 + 50 )/25
= 87/25
I hope this helps you.
:)
I used x instead of theta.
according to the problem given,
4 sinx = 3 cosx ---( 1 )
sinx / cos x = 3/ 4
tan x = 3/4 --- ( 2 )
we know that
sec² x = 1 + tan² x
= 1 + ( 3/4 )²
= ( 16 + 9 ) / 16
= 25/ 16
sec x = 5/4 ---- ( 3 )
cos x = 4/5 ---( 4 )
since cos x = 1/ sec x
ii ) put ( 4 ) in ( 1 ), we get
4 sin x = 3 × ( 4/5)
sin x = ( 3× 4 ) /( 4 × 5)
sin x = 3/5 --- ( 5 )
iii ) cot² x - cosec² x
= 1 /tan² x - 1 / sin² x
= 1 / ( 3/4)² - 1 / (3/5)²
= ( 16 / 9) - ( 25/ 9)
= (16-25)/9
= -9/9
= -1
iv )4cos² x - 3 sin² x + 2
= 4 × (16/25) - 3 × (9/25) +2
= 64/25 - 27/25 + 2
= ( 64 - 27 + 50 )/25
= 87/25
I hope this helps you.
:)
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