plzzz ans......trignometry.......thknk u
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If secA = sqrt(2)
cosA = 1/sqrt(2)
Opposite side = sqrt(2 - 1) = 1
SinA = 1/sqrt(2)
TanA = 1
(3*(1/sqrt(2))^2 + 5*1^2) / (4*1^2 - (1/sqrt(2))^2)
=(3/2 + 5) / (4 - 1/2)
= (13/2) / (7/2)
= 13/7
cosA = 1/sqrt(2)
Opposite side = sqrt(2 - 1) = 1
SinA = 1/sqrt(2)
TanA = 1
(3*(1/sqrt(2))^2 + 5*1^2) / (4*1^2 - (1/sqrt(2))^2)
=(3/2 + 5) / (4 - 1/2)
= (13/2) / (7/2)
= 13/7
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