plzzz anss .. i m in big problm due to this question. if someone answered me in easy step definitely i ll make them brainlist
Attachments:
Answers
Answered by
3
Note: I am writing theta as a.
Given x sina = ycosa ------- (1)
Given x sin^3 a + y cos^3 a = sina cosa ------ (2)
Substitute (1) in (2), we get
= > x sin a * sin^2a + y cos^3 a = sina * cos a
= > y cos a * sin^2 a + y cos^3 a = sina * cos a
= > y cos a(sin^2a + cos^2a) = sina * cosa
= > y cos a(1) = sin a * cos a
= > y = sin a
Substitute y = sin a in (1), we get
= > x sina = (sina)(cosa)
= > x = cos a.
Now,
= > x^2 + y^2 = sin^2a + cos^2a
= 1.
Hope this helps!
Given x sina = ycosa ------- (1)
Given x sin^3 a + y cos^3 a = sina cosa ------ (2)
Substitute (1) in (2), we get
= > x sin a * sin^2a + y cos^3 a = sina * cos a
= > y cos a * sin^2 a + y cos^3 a = sina * cos a
= > y cos a(sin^2a + cos^2a) = sina * cosa
= > y cos a(1) = sin a * cos a
= > y = sin a
Substitute y = sin a in (1), we get
= > x sina = (sina)(cosa)
= > x = cos a.
Now,
= > x^2 + y^2 = sin^2a + cos^2a
= 1.
Hope this helps!
siddhartharao77:
:-)
bhai thnku
Welcome!
:)
bhai there is no option for making as brainlist
i want to make you as brainlist
if one more user answers then it will come..if only one has answered, then option will come after 7 days..
Ohhh wet for 7 days bhai or may wet for someone answer i ll definitely make you as brainlist
Thank you :-)
hmm
Similar questions