Question

plzzz answer fast.....​

Answer 1

Step-by-step explanation:

$= > {x}^{a} \times {x}^{b} = { {x}^{a} }^{b} \\ = > {x}^{a + b} = {x}^{ab} \\ = > compare \: powers \\ = > a + b = ab \\ = > sqaure \: both \: side \\ = > {a + b}^{2} = {ab}^{2} \\ = > {a}^{2} + 2ab + {b}^{2} = {a}^{2} {b}^{2} \\ = > \frac{ {a}^{2} }{ {a}^{2} {b}^{2} } + \frac{2ab}{ {a}^{2} {b}^{2} } + \frac{ {b}^{2} }{ {a}^{2} {b}^{2} } = 1 \\ = > \frac{1}{ {b}^{2} } + \frac{2}{ab} + \frac{1}{ {a}^{2} } = 1 \\ = > \frac{1}{ab} ( \frac{a}{b} + 2 + \frac{b}{a}) = 1 \\ = > \frac{a}{b} + 2 + \frac{b}{a} = ab \\ = > \frac{a}{b} + \frac{b}{a} = ab - 2$

Answer 2

Answer:

hiii

your answer

Step-by-step explanation:

hope it helps