Question

plzzz answer fast....want help ​

Answer 1

Answer:

according to question :-

we know that a triangle is said to be a right angled triangle when the squares of base and height is equal to the square of hypotenuse

so

to prove triangle ABC is right angled triangle :-

9^2 + 40^2 = 41^2

81 + 1600 = 1681

1681 = 1681

now since height ^2 + base ^2 = hypotenuse ^2

therefore

this shows that triangle ABC is a right angled triangle

hope you understand plz thank my answer

Answer 2

Applying Pythagoras Theorem,

if ,

$base {}^{2} + perpendicular {}^{2} = hypotenuse {}^{2}$

ATQ,

$(9 {}^{2} + 40 {}^{2}) = 41 {}^{2}$

=> (81+ 1600) = 1681

=> 1681 = 1681

LHS = RHS

hence, ABC is a right angled triangle. where angle B= 90°

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