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first we draw both figure. perimeter of square is equal to 4 *side. we get the side of the square=68. then find the area of a square =side x side. we get the area of square(=4624)
it is given that the side of square is 18 cm more than the width of rectangle. show me - the width of rectangle by the side of square. we get the width of rectangle. then we find the length of rectangle by is the formula =2(l+b) we get the length 86 centimetre. then find the area of rectangle(=l x b=86*50=4360. )then find the difference between the two areas=area of square minus area of rectangle=(4624-4360=324)
it is given that the side of square is 18 cm more than the width of rectangle. show me - the width of rectangle by the side of square. we get the width of rectangle. then we find the length of rectangle by is the formula =2(l+b) we get the length 86 centimetre. then find the area of rectangle(=l x b=86*50=4360. )then find the difference between the two areas=area of square minus area of rectangle=(4624-4360=324)
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jarvis5:
this is the answer
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