Question

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Answer 1

Explanation:amount of heat required to convert 200 gram of ice at zero degree celsius to 200 gram of water at zero degree celsius = 67200J

Time = 1min or 60s

Rate of heat supply = 1120J/s

Heat required to raisebthe temperature of 200 gram of water at zero degree celsius to 200 gram of water at 20 degree Celsius = 16736 J

So, time taken = 16736/1120 = 14.9s

Approximately equal to 15 seconds.