plzzz answer it really really fast
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let x and y be 11a and 19a
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
Dsnyder:
but I didnt think u cannot know this simple thing
it was by mistake
I know it was BY MISTAKE
but in question it is not given 90 anywhere
OH..
se
in the question you can apply the angle sum property?
ΔABD
11a+19a+90°=180
11a+19a+90°=180
u can transpose 90 to the other side
ok thanks Dsnyder...
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i need free points sorry
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