Question

plzzz answer it ...... where the sides are 9 28 40

Answer 1

area of trapezium is $\frac{1}{2} h(a+b)$

so, h = 9

a = 28

b = 40

$\frac{1}{2}(9)(28)(40)$

5040 $cm^{2}$

Answer 2

ABCD is a Trapezium

Area of Trapezium= sum of parallel sides* height/2

Height=9cm(it is ⊥(90°⇒perpendicular) to the base )

Two parallel side⇒40cm and 28 cm

So, ⇒40+28*9/2

⇒68*9/2

⇒612/2

⇒306

Therefore area of Trapezium ABCD= 306cm²

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