plzzz answer me..any expert?
Attachments:
![](https://hi-static.z-dn.net/files/d88/6568861ac03de84242b0e223e2f6a285.jpg)
Answers
Answered by
3
answer:- 2 /a xλD
============================
ARBAAZ BHAI *-* SCHOOL TALK ? PARVDUBEY ?
For minima :
ΔX=L/2
LAMBDA=L(PLEASE ASSUME. NOT ABLE TO FIND LAMBDA ANSWERING AFTER A LONG TIME).
so,
a sin∅=L/2
=>sinФ=tanФ=Y/D ( pretend from 1)....2
=>from 1 and 2nd ..~see
=>y=LD/a
=>the second will form y =LD/a exactly below of the central maxima.
width of central maxima ; 2L D/a
------------------------------
bro lambda=L ...
-----------------------------
thanks~
hope this helps you~!____________
++++++++++++++++++++++++++++++++++++++
Answered by
0
Answer:
please inbox me...........
Similar questions