Question

plzzz answer me..any expert?​

Answer 1

answer:- 2  /a xλD

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ARBAAZ BHAI *-* SCHOOL TALK ? PARVDUBEY ?

For minima :

ΔX=L/2

LAMBDA=L(PLEASE ASSUME. NOT ABLE TO FIND LAMBDA ANSWERING AFTER A LONG TIME).

so,

a sin∅=L/2

=>sinФ=tanФ=Y/D ( pretend from 1)....2

=>from 1 and 2nd ..~see

=>y=LD/a

=>the second will form y =LD/a exactly below of the central maxima.

width of central maxima ; 2L D/a

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bro lambda=L ...

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thanks~

hope this helps you~!____________

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Answer 2

Answer:

please inbox me...........