Question

plzzz...answer my questionn......​

Answer 1

Answer:

Ans. (A)

Solution:

Sum of r terms in an AP is given by : Sr=r2[2A+(r−1)D]where A = first termand D= common differenceGiven that: Saa2=ca2[2A+(a−1)D]a2=c2A+(a−1)D2a=c2A+(a−1)D=2ac ……………………………(i)Similarly, for Sbb2=c, 2A+(b−1)D=2bc ……………………………(ii)Solvig eq.s (i) and (ii) for A and D, we get:A=c and D=2cNow, Sc=c2[2A+(c−1)D]=c2[2c+(c−1)2c]=c2x2cx[1+c−1]=c3

Step-by-step explanation:

Hope this will help uh☺☺