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q = ne
2 culamb = n x 1.6 x 10^-19
so
n(no. of electron) = 2/(1.6 x 10^-19)
n = 1.25 x 10^+19
i hope it will help you
regards
2 culamb = n x 1.6 x 10^-19
so
n(no. of electron) = 2/(1.6 x 10^-19)
n = 1.25 x 10^+19
i hope it will help you
regards
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