Question

Plzzz answer quickly

Answer 1

your solution and the figure is in image

Answer 2

Hey !


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Tangents drawn from an external point to a circle are equal.
⇒ AD = AF, BD = BE, CE = CF.
 
Let AD = AF = a 
BD = BE = b 
CE = CF = c 
 
( 1 ) -------AB = AD + DB = a + b = 8 --



( 2 ) ---------. BC = BE + EC = b + c = 10 ---


( 3 ) ----------AC = AF + FC = a + b = 12 ---
 
Adding (1), (2) and (3), we get
2 (a + b + c) = 30
⇒ (a + b + c) = 15 -------- (4)
 



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Subtracting (1) from (4), we get c = 7


Subtracting (2) from (4), we get a = 5



Subtracting (3) from (4), we get b = 3



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Therefore, AD = a = 5 cm, BE = b = 3 cm, CF = c = 7 cm