Question

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Answer 1

Answer:

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Answer 2

Answer:

i) Given ; ΔABC and ΔDBC are two triangles such that AB=BD and AC=CD.

To show, ΔABC≅ΔDBC

proof;

in triangle DBM and triangle AMC,

AB=BC (Given)

AC=CD (Givne)

BC=BC ( Common )

Therefore, by SSS criterion of congruency, triangle ABC is congruent to triangle DBC.

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