plzzz answer the question
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Let original average speed = x km/hr
ATQ
63/x + 72/(x+6) = 3
63x + 63*6 + 72x = 3x(x+6)
divide by 3 to simplify
21x + 63*2 + 24x = x(x+6)
45x + 126 = x^2 + 6x
x^2 - 39x - 126 = 0
x^2 -42x +3x -126 = 0
x(x- 42) + 3(x-42) = 0
(x+3)*(x-42) = 0
>> x= 42km/hr as speed cant be negative.
ATQ
63/x + 72/(x+6) = 3
63x + 63*6 + 72x = 3x(x+6)
divide by 3 to simplify
21x + 63*2 + 24x = x(x+6)
45x + 126 = x^2 + 6x
x^2 - 39x - 126 = 0
x^2 -42x +3x -126 = 0
x(x- 42) + 3(x-42) = 0
(x+3)*(x-42) = 0
>> x= 42km/hr as speed cant be negative.
neosingh:
where is the prob
in LHS
HOW it becam 63x +63*6 +72x
before cross multiplying i took the LCM
63(x+6) + 72x
okk
thnxx
you are in which class
+2
ooo
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