Question

plzzz answer the question fasttttt

Answer 1

let the numbers be a-3d,a-d,a+d,a+3d
therefore sum of 4s=32
a-3d+a-d+a+d+a+3d=32
4a=32
a=8
now, (a-3d)(a+3d)/(a-d)(a+d)=7/15
a^2-9d^2/a^2-d^2=7/15 ( (a+b)(a-b)=a^2-b^2
on cross multiplying
15a^2-135d^2=7a^2-7d^2
8a^2=128d^2
putting value of a from above
8(8)^2=128d^2
=4=d^2
d=4,-4
therefore , on putting d=4 numbers are
-4,4,12,20
on putting d=-4, numbers=
20,12,4,-4
hence numbers are same in both cases which is -4,4,12,20.
plz mark it as brainliest if u find this as helpful:):-););)