Question

plzzz answer these 2 questions. i'm so confused

Answer 1

The 5th question doesn't have any data that could give us the number of moles required, so yeah, None should be correct.

I dunno if the book you're using follows some convention though. If it does, there might be an obtainable answer.

The 6th question:

Oxalic acid has n-factor 2 (dibasic acid), so its Normality and Molarity are related as:

Normality = 2 * Molarity

So for 0.1 N solution, Molarity is 0.1/2 M = 0.05M.

In 1000mL, that is 1L, for concentration 0.05M, the number of moles = 0.05 * 1 moles = 0.05 moles.

Now the mass of one mole oxalic acid (dihydrate) = 2*1 + 2*12 + 4*16 + 2(2*1 + 16) g/mol = 126 g/mol.

So, mass required = moles * molar mass = 0.05 * 126 g = 6.3 g (c).