Math, asked by ashu1208364, 1 year ago

plzzz answer this plzzzzz fast

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Answered by Anonymous
5

Solution

  =  > \frac{5 \times 25  {}^{n + 1}  - 25 \times 5 {}^{2n}  }{5 \times 5 {}^{2n + 3}  - 25 {}^{n + 1} }  \\  =  >  \frac{5   \times5 {}^{2n + 2}   - 5 {}^{2} \times 5 {}^{2n}  }{5 \times 5 {}^{2n + 2 + 1}  - 5 {}^{2n + 2} }  \\  =  >  \frac{5 \times 5 {}^{2n + 2}  - 5 {}^{2n + 2} }{5 \times 5 \times5 {}^{2n + 2}   - 5 {}^{2n + 2} }  \\  =  >  \frac{5 {}^{2n + 2} (5 - 5 {}^{2} )}{5 {}^{2n + 2} (25 - 1)}  \\  =  >  \frac{ -2 0}{24}  \\  =  >  \frac{ - 5}{6}

Answered by shazaya
1

#hope it helps

#plzfollowme

#shazayarao

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