Question

plzzz answer this question. but don't give answer like ask your teacher etc

Answer 1

from given equation22
a=1,b=15,c=1
x=(-b+root b^2-4ac)/2 or(-b-root b^2-4ac)/2
x=(-15+root 221 )/2 or (-15-root 221)/2
then alpha (A)=(-15+root221)/2
beta(B)=(-15-root221)/2
now put the value alpha and beta
(1/A-15)^2+(1/B-15)^2
=(1/A^2-2×1/A×15+225)+(1/B^2-2×1/B×15+225)
=[{4/(-15+root221)^2}-(60/-15+root221)+225]+[{4/(-15-root221)^2}-(60/-15-root221)+225]
=[4{(15+root221)^2}+4{(15-root221)^2}]/[(15^2-root221^2)]^2+[{60/15-root221}+{60/15+root 221)]+225+225
=[8(225-221)/(225-221)^2]+(60×30/4)+550
=[8×4/16]+450+550
=2+900=902
its my answer so i have 2 more comes up.i will try again.give your comment if you not understood