Math, asked by reshul, 1 year ago

plzzz answer to this

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Answered by akpranav
1

2) the coordinate of the point on y axis is ( 0, -3)

3) x+6 = 0

x = -6

p(x) = x³ + 3x² + 4x + k

p(-6) =

(-6)³ + (-6)²(3) + 4(-6) + k = 0

-216 + 36*3 - 24 + k = 0

-240 + 108 + k = 0

-132 + k = 0

k = 132

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