Question

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A ball is thrown vertically upwards from the top of a tower with a speed of 100 m/s. It strikes the pond near
the base of the tower after 25 second. The height of the tower is
(2) 125 m​

Answer 1

Answer:

The distance is given as,

s=ut−

2

1

gt

2

s=100×25−

2

1

×10×(25)

2

s=−625m

The distance is negative because the final position of ball lies below the initial position.

Thus, the height of the tower is 625m.

Answer 2

Answer:

The distance is given as,

s=ut−

2

1

gt

2

s=100×25−

2

1

×10×(25)

2

s=−625m

The distance is negative because the final position of ball lies below the initial position.

Thus, the height of the tower is 625m