plzzz answers the last question question
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by distance formula,
√ (x2-x1)²+ ( y2-y1)² = 10 units
√ 8 ² +( y+3 ) ² = 10
64 + y² + 3² + 6y = 100
y² +3²+6y = 100-64
y + 3 = 6
y = 3
√ (x2-x1)²+ ( y2-y1)² = 10 units
√ 8 ² +( y+3 ) ² = 10
64 + y² + 3² + 6y = 100
y² +3²+6y = 100-64
y + 3 = 6
y = 3
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