Math, asked by letsgameupatngc, 10 months ago

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Answered by sahuraj457
1

s =  \sqrt{ { (x_{1} } -  x_{2}) ^{2}  + (  y_{1} -  y_{2}  )^{2} }  \\ 10 =  \sqrt{ ({10 - 2})^{2} +  {(y + 3)}^{2}  }  \\ 100 = 64 +  {(y + 3)}^{2}  \\ 36 =  {(y + 3)}^{2}  \\  +  - 6 = y + 3 \\ y =  - 3 +  - 6 \\ y = 3 \: or \:  - 9
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Answered by ashish5597
0
by distance formula,
√ (x2-x1)²+ ( y2-y1)² = 10 units
√ 8 ² +( y+3 ) ² = 10
64 + y² + 3² + 6y = 100
y² +3²+6y = 100-64
y + 3 = 6
y = 3
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