Question

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Answer 1

Answer:-

• Given that Cuboidal Tin box has dimentions .

Concept:-

• Application of TSA or Total Surface Area.

Let's Do!

• Given that length is l.
• Given that breadth is b.
• Given that height is h.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$ Same, as dimentions given are also same.

• Now, we need 10 such boxes. So, we will multiply it with 10.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl) \times 10}}$

$\boxed{\sf{ TSA \ Cuboid = 20(lb+bh+hl)}}$ is the required answer.

More to Know:-

• CSA of a Cuboid is $\sf{2(l+b) \times h}$
• Volume is $\sf{l \times b \times h}$
• Here, l, b and h are same.

Answer 2

Given :

A cuboidal tin box has dimentions l cm × b cm × h cm

To find :

TSA of metal sheet required to make 10 such boxes

Solution :

We have,

• Length is l
• Breadth is b
• Height is h

Total surface area of cuboid = 2 (lb + bh + hl)

Here,

Total surface area of cuboid = 2 (lb + bh + hl) [ Same, because dimensions given are also same ]

We need 10 such boxes, so, multiply it with 10.

⇒ Total surface area of cuboid = 2 (lb + bh + hl) × 10

⇒ Total surface area of cuboid = 20 (lb + bh + hl)

∴ 20 (lb + bh + hl) is the total surface area of metal sheet required to make 10 such boxes.