Question

plzzz fast factorise.... ​

Answer 1

I hope It will help you.

Answer 2

Answer:

[3 (a+b+c+1)][3(a+b+c-1)]

Step-by-step explanation:

9(a+b+c)^2 -9 = 3(a+b+c)^2 =3^2

Now the above expression id in the form of a^2 -b^2 =(a+b)(a-b)

=[3(a+b+c)+3][3(a+b+c)-3] where a = 3(a+b+c) and  b = 3

=[3 (a+b+c+1)][3(a+b+c-1)]