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Given :-
- Velocity of the ball = 5 m/s
- Height of tower = 10 m
- acceleration due to gravity = 10 m/s²
To Find :-
- The Vertical and horizontal components of velocity.
- The velocity of ball
Solution :-
Using third equation of motion ,
Where ,
- v is final velocity
- u is initial velocity
- a is acceleration
- s is distance/height
We have ,
u = 0 m/s [initial velocity along y axis is 0 m/s]
a = g = 10 m/s²
s = h = 10 m
Substituting the values :-
So , Vertical component of velocity of ball is m/s.
Now We have ,
m/s
vₓ = 5 m/s [Horizontal component remains constant]
Now , Calculating the velocity of ball ,
Hence ,
- The Horizontal and vertical components of velocity of given ball are 5 m/s and m/s . The velocity of ball is 15 m/s. So , Option(3) is the required answer
Answered by
17
Given:-
- Height (h) of the tower= 10m
- acceleration due to gravity(g)= 10ms^-1
- Velocity of the ball = 5m/s
To Find:-
- The velocity of the ball when it reaches the ground
Solution:-
For Finding the velocity we will use the Velocity Calculator Formula
Where,
We Have,
Substituting the values:-
Vertical Component of velocity of ball is 10√2m/s
Now,
Now, The Velocity of ball=
Hence,
The velocity of ball is 15 ms^-1
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