Question

plzzz give me ans ques no 1

Answer 1

assume , y = vx

differentiate this equation wrt x ..
you will get ..

$\frac{dy}{dx} = v + x \times \frac{dv}{dx}$

put these values in your questions you will differential eqn in v & x , then solve this eqn... you will get the answer

=> ((1+v)/(1-v)) dv = dx / x

=> ((-1 + 2/(1-v)) dv = dx / x

now integrating both side you will get ...

-2 log (1-v) - v = log (x) + k

after solving this eqn you will get the answer..