plzzz give me answer fast
Attachments:
Answers
Answered by
3
Step-by-step explanation:
Given: 2cos²θ - cos⁴θ + sin⁴θ
= sin⁴θ - cos⁴θ + 2cos²θ
= (sin²θ)² - (cos²θ)² + 2cos²θ
∴ a² - b² = (a + b)(a - b)
= (sin²θ + cos²θ)(sin²θ - cos²θ) + 2cos²θ
∴ sin²θ + cos²θ = 1
= sin²θ - cos²θ + 2cos²θ
= sin²θ + cos²θ
= 1.
Hope it helps!
Answered by
0
2cos²θ - cos⁴θ + sin⁴θ
= sin⁴θ - cos⁴θ + 2cos²θ
= (sin²θ)² - (cos²θ)² + 2cos²θ
∴ a² - b² = (a + b)(a - b)
= (sin²θ + cos²θ)(sin²θ - cos²θ) + 2cos²θ
∴ sin²θ + cos²θ = 1
= sin²θ - cos²θ + 2cos²θ
= sin²θ + cos²θ
= 1.
Similar questions