Question

plzzz give me the solution of above mentioned question...​

Answer 1

Answer:

In triangle,AOB,

Given angle B<angle A

Now in a triangle, side opposite to smallest angle is smallest while side opposite to largest angle is largest.

Therefore, if angle B<angle A so

side AO < side BO...... Equation 1

Similarly in triangle DOC,

angle C < angle D

so side OD < side OC ..... Equation 2

Adding equation 1 and 2,

side AO+side OD < side BO+sideOC

Now AO+OD = AD

BO + OC = BC

So, AD<BC

Hence proved