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Given
Let 1st digit =x
and 2nd digit=> y=2x -----------------(1)
digit is: 10x+y ------(2) considering place values
interchange digits:
y becomes 10 times,
y*10
10y+x ------------- (3)
Sum of (2) and (3) is 99 , Given
10y+x+10x+y=99
write y interms of x (from 1 above)
10(2x) + x +10x + 2x = 99
20x+x+10x+2x=99
33x=99
x=99/33 = 3
So first digit is 3, 2nd digit y=2x = 2x3 = 6
Verify:
36+63=99
Step-by-step explanation:
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