plzzz give the answer quickly
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let the initial charge be Q
and the charge on one side be q so charge on another side will be Q - q
(see the diagram above)
so,
the force between them will be
F = 1/4πE * q(Q-q)/r^2
(E = permitivity of free space)
if force is maximum means the derivative or differentiation should be zero
i.e.,
df/dq = 0
d( 1/4πE * q(Q-q)/r^2)/dq = 0
1/4πE*r^2 * d(qQ-q^2)/dq = 0
1/4πE*r^2 * (Q - 2q) = 0
Q - 2q = 0
Q = 2q
q = Q/2
so the charge on the individual will be the half of the total charge.
♡♥♡♥♡♥♡♥♡♥♡♥♡♥♡
and the charge on one side be q so charge on another side will be Q - q
(see the diagram above)
so,
the force between them will be
F = 1/4πE * q(Q-q)/r^2
(E = permitivity of free space)
if force is maximum means the derivative or differentiation should be zero
i.e.,
df/dq = 0
d( 1/4πE * q(Q-q)/r^2)/dq = 0
1/4πE*r^2 * d(qQ-q^2)/dq = 0
1/4πE*r^2 * (Q - 2q) = 0
Q - 2q = 0
Q = 2q
q = Q/2
so the charge on the individual will be the half of the total charge.
♡♥♡♥♡♥♡♥♡♥♡♥♡♥♡
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