Math, asked by vaishnavi45, 1 year ago

plzzz give the answer to be brainlist

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Answered by boney2
1
We have,
AP//BQ//CR,
In triangle ABQ and PQB we have,
area(ABQ)=area(PQB). ...1 [ sincetriangles on same base and between same parallels have equal area.]
Similarly in triangle BQC &QBR e get
area (BQC)=area(QBR)....2 [ sincetriangles on same base and between same parallels have equal area.]
On adding eqn 1 & 2 we get,
area(ABQ+BQC)=area(PQB+QBR)
area(AQC)=area(PBR)
Hence, proved.
mark my answer as brainliest. Thanks

vaishnavi45: thanks very very much
vaishnavi45: you are brainlist
vaishnavi45: but when option come i will mark
boney2: welcome
boney2: i hope this answer may have helped u
vaishnavi45: okk when option came i will mark you as brainlist
vaishnavi45: yes it helped me
Answered by nethranithu
0
Hlo friend

Here ur answer which i attached u

Hope this helps u a lot

Plz mark as brainlist
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