Physics, asked by deepeshthakkarpdekwr, 1 year ago

Plzzz Guys help me in this question

Physics

Chapter Gravitation

Numerical

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Answered by reetu2291
0

t=3seconds

v=0m/s

a=-9.8m/s2

u=?

v=u+at

0=u+3*-9.8

0=u-29.4

u=29.4m/s


2as = v2 - u2

2*-9.8*s = (0+29.4)(0-29.4)

-19.6s=29.4 *-29.4

s = 44.1 m




Answered by guptakushi
0

Final velocity = 0m/s

Time taken to reach the highest point = 6/2 seconds = 3 seconds

Acceleration due to gravity = -9.8m/s^2

a) v = u+ gt

0 = u + (-9.8)*3

0= u- 29.4

u = 29.4m/s

b) 2gh = v^2-u^2

2*(-9.8)*h = 0^2 - (29.4)^2

-19.6h = - 864.36

h = 44.1m

c) h = ut + 1/2 gt^2

h = 0*1+1/2*9.8*1^2

h = 4.9m


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