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Physics
Chapter Gravitation
Numerical
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t=3seconds
v=0m/s
a=-9.8m/s2
u=?
v=u+at
0=u+3*-9.8
0=u-29.4
u=29.4m/s
2as = v2 - u2
2*-9.8*s = (0+29.4)(0-29.4)
-19.6s=29.4 *-29.4
s = 44.1 m
Answered by
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Final velocity = 0m/s
Time taken to reach the highest point = 6/2 seconds = 3 seconds
Acceleration due to gravity = -9.8m/s^2
a) v = u+ gt
0 = u + (-9.8)*3
0= u- 29.4
u = 29.4m/s
b) 2gh = v^2-u^2
2*(-9.8)*h = 0^2 - (29.4)^2
-19.6h = - 864.36
h = 44.1m
c) h = ut + 1/2 gt^2
h = 0*1+1/2*9.8*1^2
h = 4.9m
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