plzzz help me.......
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x=35(because <BDC is 35)
y=180-(35+80)
=65
z=110.
hope this helps......
y=180-(35+80)
=65
z=110.
hope this helps......
Answered by
1
Hello there!
mudit11 here to help.
______________________________
The angle BDC and DBA form alternative angles as AB is parallel to CD.
✓ So, X = 35°
Now, we know that sum of all the angles na triangle is 180°
So, BAD + ABD + BDA = 180°
= 80° + 35 ° + Y = 180
Y = 180 - 115
✓ Y = 65°
Now, Angle DBC = y - 30°
DBC = 65 - 30
DBC = 35°
Finally, in ∆ DCB
35° + 65° + Z = 180°
100 + Z = 180
✓ Z = 80°
______________________________
I hope this helps.
mudit11 here to help.
______________________________
The angle BDC and DBA form alternative angles as AB is parallel to CD.
✓ So, X = 35°
Now, we know that sum of all the angles na triangle is 180°
So, BAD + ABD + BDA = 180°
= 80° + 35 ° + Y = 180
Y = 180 - 115
✓ Y = 65°
Now, Angle DBC = y - 30°
DBC = 65 - 30
DBC = 35°
Finally, in ∆ DCB
35° + 65° + Z = 180°
100 + Z = 180
✓ Z = 80°
______________________________
I hope this helps.
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