Question

plzzz help me fast I have summit it today

Answer 1

let x be
$p(0) = (0 - 2)2 \: \: - (0 - 2)2 \\ \: \: \: \: p(0) \: \:= (0 - 4) - (0 - 4) \\ p(0)= 0 - 0 \\ p(0) = \: 0$

Answer 2

p (x) = (x-2)^2-(x+2) ^2
this is in the form of a^2-b^2

p (x)=(x-2+x+2)(x-2-(x+2))
p (x)=2x (x-2-x-2)
p (x)=2x (-4)
p (x)=-8

p (x)=0
-8x=0
x=0

x=0 is the zero of the polynomial p (x)