plzzz help me frnds in this queee it's so important.
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1 mole (18 grams) of H₂O contains Avogadro number of molecules
→ 6 x 10²³ molecules
so, 6 x 10²³ molecules of H₂O weigh 18 grams
then, 1 molecule of H₂O will weigh 18/(6 x 10²³) = 3 x 10⁻²³ grams
Therefore 3 x 10⁻²³ grams is the weight of 1 molecule of water.
Hence, Volume occupied by it = weight/density = 3 x 10⁻²³/1 = 3 x 10⁻²³ cm³
The volume occupied by 1 molecule of H₂O is 3 x 10⁻²³ cm³
→ 6 x 10²³ molecules
so, 6 x 10²³ molecules of H₂O weigh 18 grams
then, 1 molecule of H₂O will weigh 18/(6 x 10²³) = 3 x 10⁻²³ grams
Therefore 3 x 10⁻²³ grams is the weight of 1 molecule of water.
Hence, Volume occupied by it = weight/density = 3 x 10⁻²³/1 = 3 x 10⁻²³ cm³
The volume occupied by 1 molecule of H₂O is 3 x 10⁻²³ cm³
siril:
please refresh the page, i did a small correction at the last
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