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as it is a regular Pentagon so the inner angel is =180°-360°÷5
=108°
thus angel B =108° and
angle C= 108°
angle A bisect by AM so
angle BAM=108°÷2=54°
now ABCM is a quadrilateral so total angle is 360°
so angle AMC =360°- {angle(B+C +BAM)}
=360°-108°-108°-54°
=90°
hope it helps you
=108°
thus angel B =108° and
angle C= 108°
angle A bisect by AM so
angle BAM=108°÷2=54°
now ABCM is a quadrilateral so total angle is 360°
so angle AMC =360°- {angle(B+C +BAM)}
=360°-108°-108°-54°
=90°
hope it helps you
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