Question

plzzz help me out!!!!​

Answer 1

Correct Question-:

• The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4. Find all the four angles.

AnswEr -:

$\boxed{\blue{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}$

Explanation-:

Given ,

• The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4.

To Find ,

The all four angles of parallelogram.

☆ Figure related to the question-:

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\end{picture}$

Solution -:

☆ Let the four angles of parallelogram be -:

1st angle -: ( Angle )¹ = 1 x ⁰

2nd angle -: ( Angle )² = 4 x ⁰

3rd angle-: ( Angle)³ = 1 x ⁰

4th angle -; ( Angle )⁴ = 4 x ⁰ .................[1]

As we know that ,

$\boxed{\blue{\sf{\star{\:Sum \:of\:all\:four\:angles\:of\:Parallelogram \:is\:360⁰}}}}$

or ,

$\boxed{\blue{\sf{\star{\:(Angle)_{1} +( Angle)_{2}+ (Angle )_{3}+ (Angle)_{4} =\:360⁰}}}}$

Here ,

1st angle -: ( Angle )¹ = 1 x ⁰

2nd angle -: ( Angle )² = 4 x ⁰

3rd angle-: ( Angle)³ = 1 x ⁰

4th angle -; ( Angle )⁴ = 4 x ⁰ .................[From 1]

Now ,

• $\pink{\sf{\rightarrow {1x + 4x + 1x + 4x = 360⁰ }}}$

• $\pink{\sf{\rightarrow { 2x + 8x = 360⁰ }}}$

• $\pink{\sf{\rightarrow {10x = 360⁰ }}}$

• $\pink{\sf{\rightarrow {x =\frac { 360}{10} }}}$

• $\pink{\sf{\rightarrow {x = 36⁰ }}}$

Therefore,

$\boxed{\blue{\sf{\star{\:x = 36⁰}}}}$

Now ,

☆ Four Angles of parallelogram are -:

1st angle -: ( Angle )¹ = 1 x = 1 × 36 = 36⁰

2nd angle -: ( Angle )² = 4 x = 4 × 36 = 144⁰

3rd angle-: ( Angle)³ = 1 x = 1 × 36 = 36⁰

4th angle -; ( Angle )⁴ = 4 x = 4 × 36⁰

Hence ,

$\boxed{\blue{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}$

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Answer 2

Answer:

Correct Question-:

The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4. Find all the four angles.

AnswEr -:

$\boxed{\orange{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}$

Explanation-:

Given ,

The four angles of a parallelogram ABCD are in the ratio of 1:4:1:4.

To Find ,

The all four angles of parallelogram.

☆ Figure related to the question-:

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\end{picture}$

Solution -:

☆ Let the four angles of parallelogram be -:

1st angle -: ( Angle )¹ = 1 x ⁰

2nd angle -: ( Angle )² = 4 x ⁰

3rd angle-: ( Angle)³ = 1 x ⁰

4th angle -; ( Angle )⁴ = 4 x ⁰ .................[1]

As we know that ,

$\boxed{\orange{\sf{\star{\:Sum \:of\:all\:four\:angles\:of\:Parallelogram \:is\:360⁰}}}}$

or ,

$\boxed{\orange{\sf{\star{\:(Angle)_{1} +( Angle)_{2}+ (Angle )_{3}+ (Angle)_{4} =\:360⁰}}}}$

Here ,

1st angle -: ( Angle )¹ = 1 x ⁰

2nd angle -: ( Angle )² = 4 x ⁰

3rd angle-: ( Angle)³ = 1 x ⁰

4th angle -; ( Angle )⁴ = 4 x ⁰ .................[From 1]

Now ,

• $\pink{\sf{\rightarrow {1x + 4x + 1x + 4x = 360⁰ }}}$

• $\pink{\sf{\rightarrow { 2x + 8x = 360⁰ }}}$

• $\pink{\sf{\rightarrow {10x = 360⁰ }}}$

• $\pink{\sf{\rightarrow {x =\frac { 360}{10} }}}$

• $\pink{\sf{\rightarrow {x = 36⁰ }}}$

Therefore,

$\boxed{\blue{\sf{\star{\:x = 36⁰}}}}$

Now ,

☆ Four Angles of parallelogram are -:

1st angle -: ( Angle )¹ = 1 x = 1 × 36 = 36⁰

2nd angle -: ( Angle )² = 4 x = 4 × 36 = 144⁰

3rd angle-: ( Angle)³ = 1 x = 1 × 36 = 36⁰

4th angle -; ( Angle )⁴ = 4 x = 4 × 36⁰

Hence ,

$\boxed{\orange{\sf{\star{\:\:All\:four\:angles\:of\:Parallelogram \:is\:36⁰,144⁰,36⁰\:and\:144⁰}}}}$

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