plzzz help me out guyzz
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Answered by
1
in Δ PQS
PS^2+QS^2=PQ^2
a^2-c^2=PS^2.....1
similarly
in Δ PRS
b^2-d^2=PS^2.....2
from 1 and 2
a^2-c^2=b^2-d^2
a^2-b^2=c^2-d^2
(a+b)(a-b)=(c+d)(c-d)
hence proved
hope this helps you
Answered by
3
hey mate
here is your answer
hope it's helpful for you
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