Question

plzzz help meee......​

Answer 1

Answer:

$\frac{1}{x + 1}+ \frac{2}{x + 2} = \frac{4}{x + 4}$

$\frac{1 \times (x + 2) + 2(x + 1)}{(x + 1)(x + 2)} = \frac{4}{x + 4}$

$\frac{x + 2+2x + 2}{x^{2}+x + 2x + 2} = \frac{4}{x +4 }$

$\frac{3x + 4}{x^{2} + 3x + 2 } = \frac{4}{x + 4}$

$(3x + 4) \times (x + 4) = 4( {x}^{2} + 3x + 2)$

$3 {x}^{2} + 4x + 12x + 16 = 4 {x}^{2} + 12x + 8$

$4 {x}^{2} - 3 {x}^{2} + 12x - 4x + 8 - 16 = 0$

${x}^{2} + 8x - 8$

${x}^{2} +8x - x - 8$

$x(x + 8) - 1(x + 8)$

$(x + 8)(x - 1)$

$x = \: - 8 \: \: \: or \: \: \: x = 1$

plz mark me as brain list.