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option b is the correct answer
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Answer:option b is the answer Explanation:Let the oxidation number of molybdenum (Mo) be x.Oxidation number of H2O2 = C2H4 = 0, O= -2 . in [MO2O4(C2H4)2(H2O2)]^-2 2X+4x(-2)+2x0+0= -22X-8= -2 or X= +3 The oxidation state of molybdenum in its oxo complex species [ MO2O4(C2H4)2(H2O2)]^-2 is. +3
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