Question

plzzz kindly help me in the problem​

Answer 1

Given :-

• A body of mass 2 kg is projected vertically upward with speed 3 m/s

To Find :-

• The Maximum gravitational potential energy of the body

Knowledge Required :-

• Maximum height attained when the body is projected vertically upwards with an initial velocity 'u' m/s under the gravitational force 'g' is given by ,

• $\\ {\boxed{\sf{H = \frac{ {u}^{2} }{2g} }}}$
• Potential energy of a body is given by ,

• $\\ {\boxed{\sf{PE = mgh}}}$

Solution :-

• Comparing the data we have with the formulas we get ,

• m = 2 kg
• u = 3 m/s
• g = 9.8 m/s²

Now Calculating maximum height attained by the body ,

$\\ : \implies \sf \: H= \frac{ {(3)}^{2} }{2(9.8)}$

$\\ : \implies \sf \: H = \frac{9}{19.6}$

$\\ : \implies{\boxed{\red{\sf{H \approx 0.46 \: m}}}}$

Now calculating the potential energy ,

$\\ : \implies \sf \: PE = (2)(9.8)(0.46)$

$\\ : \implies{\underline{\boxed{\pink {\sf{PE \approx \:9\:J }}}}} \: \bigstar$

Hence ,

• The maximum gravitational potential energy of the body is 9 J

Answer 2

A rigid body of mass m is moving in a circle of radius r with a constant speed v.The force on the body is and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle......