Question

plzzz koi kardo....1 hone sevi chalegi...​

Answer 1

Answer:

Step-by-step explanation:

sec²x = 1 + tan²x and cosec²x = 1 + cot²x

\text{so,}\\\frac{1+cot^2a-1-tan^2a}{1+cot^2a+1+tan^2a}\\\\=\frac{1-tan^4a}{2tan^2a+1+tan^4a}

= ( 1 - 1/√5⁴)/(2×1/√5² + 1 + 1/√5⁴)

= (24/25)/(2/5 + 1 + 1/25)

= (24/25)/(10 + 25 + 1)/25

= 24/36

= 2/3